6(n+1)+3=2(3n-1)+11

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Solution for 6(n+1)+3=2(3n-1)+11 equation: 



6(n+1)+3=2(3n-1)+11

We move all terms to the left:

6(n+1)+3-(2(3n-1)+11)=0

We multiply parentheses

6n-(2(3n-1)+11)+6+3=0



We calculate terms in parentheses: -(2(3n-1)+11), so:

2(3n-1)+11

We multiply parentheses

6n-2+11

We add all the numbers together, and all the variables

6n+9

Back to the equation:

-(6n+9)



We add all the numbers together, and all the variables

6n-(6n+9)+9=0

We get rid of parentheses

6n-6n-9+9=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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