6(n+1)+(n+3)=5(n+1)+2

Solution for 6(n+1)+(n+3)=5(n+1)+2 equation:

6(n+1)+(n+3)=5(n+1)+2

We move all terms to the left:

6(n+1)+(n+3)-(5(n+1)+2)=0

We multiply parentheses

6n+(n+3)-(5(n+1)+2)+6=0

We get rid of parentheses

6n+n-(5(n+1)+2)+3+6=0


We calculate terms in parentheses: -(5(n+1)+2), so:

5(n+1)+2

We multiply parentheses

5n+5+2

We add all the numbers together, and all the variables

5n+7

Back to the equation:

-(5n+7)


We add all the numbers together, and all the variables

7n-(5n+7)+9=0

We get rid of parentheses

7n-5n-7+9=0

We add all the numbers together, and all the variables

2n+2=0

We move all terms containing n to the left, all other terms to the right

2n=-2

n=-2/2

n=-1