6(m-2)+14=3(m-2)-10

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Solution for 6(m-2)+14=3(m-2)-10 equation: 



6(m-2)+14=3(m-2)-10

We move all terms to the left:

6(m-2)+14-(3(m-2)-10)=0

We multiply parentheses

6m-(3(m-2)-10)-12+14=0



We calculate terms in parentheses: -(3(m-2)-10), so:

3(m-2)-10

We multiply parentheses

3m-6-10

We add all the numbers together, and all the variables

3m-16

Back to the equation:

-(3m-16)



We add all the numbers together, and all the variables

6m-(3m-16)+2=0

We get rid of parentheses

6m-3m+16+2=0

We add all the numbers together, and all the variables

3m+18=0

We move all terms containing m to the left, all other terms to the right

3m=-18

m=-18/3

m=-6

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