6(m+20)+2m=-10-2m

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Solution for 6(m+20)+2m=-10-2m equation: 



6(m+20)+2m=-10-2m

We move all terms to the left:

6(m+20)+2m-(-10-2m)=0

We add all the numbers together, and all the variables

6(m+20)+2m-(-2m-10)=0

We add all the numbers together, and all the variables

2m+6(m+20)-(-2m-10)=0

We multiply parentheses

2m+6m-(-2m-10)+120=0

We get rid of parentheses

2m+6m+2m+10+120=0

We add all the numbers together, and all the variables

10m+130=0

We move all terms containing m to the left, all other terms to the right

10m=-130

m=-130/10

m=-13

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