6(k-4)-7k=32-2(k+8)

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Solution for 6(k-4)-7k=32-2(k+8) equation: 



6(k-4)-7k=32-2(k+8)

We move all terms to the left:

6(k-4)-7k-(32-2(k+8))=0

We add all the numbers together, and all the variables

-7k+6(k-4)-(32-2(k+8))=0

We multiply parentheses

-7k+6k-(32-2(k+8))-24=0



We calculate terms in parentheses: -(32-2(k+8)), so:

32-2(k+8)

determiningTheFunctionDomain
-2(k+8)+32

We multiply parentheses

-2k-16+32

We add all the numbers together, and all the variables

-2k+16

Back to the equation:

-(-2k+16)



We add all the numbers together, and all the variables

-1k-(-2k+16)-24=0

We get rid of parentheses

-1k+2k-16-24=0

We add all the numbers together, and all the variables

k-40=0

We move all terms containing k to the left, all other terms to the right

k=40

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