6(k-3)=(4k+5)

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Solution for 6(k-3)=(4k+5) equation: 



6(k-3)=(4k+5)

We move all terms to the left:

6(k-3)-((4k+5))=0

We multiply parentheses

6k-((4k+5))-18=0



We calculate terms in parentheses: -((4k+5)), so:

(4k+5)

We get rid of parentheses

4k+5

Back to the equation:

-(4k+5)



We get rid of parentheses

6k-4k-5-18=0

We add all the numbers together, and all the variables

2k-23=0

We move all terms containing k to the left, all other terms to the right

2k=23

k=23/2

k=11+1/2

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