6(k-3)-7=4K-(3k-1)

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Solution for 6(k-3)-7=4K-(3k-1) equation: 



6(k-3)-7=4-(3k-1)

We move all terms to the left:

6(k-3)-7-(4-(3k-1))=0

We multiply parentheses

6k-(4-(3k-1))-18-7=0



We calculate terms in parentheses: -(4-(3k-1)), so:

4-(3k-1)

determiningTheFunctionDomain
-(3k-1)+4

We get rid of parentheses

-3k+1+4

We add all the numbers together, and all the variables

-3k+5

Back to the equation:

-(-3k+5)



We add all the numbers together, and all the variables

6k-(-3k+5)-25=0

We get rid of parentheses

6k+3k-5-25=0

We add all the numbers together, and all the variables

9k-30=0

We move all terms containing k to the left, all other terms to the right

9k=30

k=30/9

k=3+1/3

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