6(k-2)-8=3k-(2k-3)

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Solution for 6(k-2)-8=3k-(2k-3) equation: 



6(k-2)-8=3k-(2k-3)

We move all terms to the left:

6(k-2)-8-(3k-(2k-3))=0

We multiply parentheses

6k-(3k-(2k-3))-12-8=0



We calculate terms in parentheses: -(3k-(2k-3)), so:

3k-(2k-3)

We get rid of parentheses

3k-2k+3

We add all the numbers together, and all the variables

k+3

Back to the equation:

-(k+3)



We add all the numbers together, and all the variables

6k-(k+3)-20=0

We get rid of parentheses

6k-k-3-20=0

We add all the numbers together, and all the variables

5k-23=0

We move all terms containing k to the left, all other terms to the right

5k=23

k=23/5

k=4+3/5

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