6(k-2)-5=6k-(5k-3)

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Solution for 6(k-2)-5=6k-(5k-3) equation:



6(k-2)-5=6k-(5k-3)
We move all terms to the left:
6(k-2)-5-(6k-(5k-3))=0
We multiply parentheses
6k-(6k-(5k-3))-12-5=0
We calculate terms in parentheses: -(6k-(5k-3)), so:
6k-(5k-3)
We get rid of parentheses
6k-5k+3
We add all the numbers together, and all the variables
k+3
Back to the equation:
-(k+3)
We add all the numbers together, and all the variables
6k-(k+3)-17=0
We get rid of parentheses
6k-k-3-17=0
We add all the numbers together, and all the variables
5k-20=0
We move all terms containing k to the left, all other terms to the right
5k=20
k=20/5
k=4

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