6(k+8)=2(2k-10)

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Solution for 6(k+8)=2(2k-10) equation: 



6(k+8)=2(2k-10)

We move all terms to the left:

6(k+8)-(2(2k-10))=0

We multiply parentheses

6k-(2(2k-10))+48=0



We calculate terms in parentheses: -(2(2k-10)), so:

2(2k-10)

We multiply parentheses

4k-20

Back to the equation:

-(4k-20)



We get rid of parentheses

6k-4k+20+48=0

We add all the numbers together, and all the variables

2k+68=0

We move all terms containing k to the left, all other terms to the right

2k=-68

k=-68/2

k=-34

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