6(k+2)=9k-5

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Solution for 6(k+2)=9k-5 equation: 



6(k+2)=9k-5

We move all terms to the left:

6(k+2)-(9k-5)=0

We multiply parentheses

6k-(9k-5)+12=0

We get rid of parentheses

6k-9k+5+12=0

We add all the numbers together, and all the variables

-3k+17=0

We move all terms containing k to the left, all other terms to the right

-3k=-17

k=-17/-3

k=5+2/3

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