6(k+1)=3(3+2k)-3

Solution for 6(k+1)=3(3+2k)-3 equation:

6(k+1)=3(3+2k)-3

We move all terms to the left:

6(k+1)-(3(3+2k)-3)=0

We add all the numbers together, and all the variables

6(k+1)-(3(2k+3)-3)=0

We multiply parentheses

6k-(3(2k+3)-3)+6=0


We calculate terms in parentheses: -(3(2k+3)-3), so:

3(2k+3)-3

We multiply parentheses

6k+9-3

We add all the numbers together, and all the variables

6k+6

Back to the equation:

-(6k+6)


We get rid of parentheses

6k-6k-6+6=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0