6(k+1)=2k+17

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Solution for 6(k+1)=2k+17 equation:



6(k+1)=2k+17
We move all terms to the left:
6(k+1)-(2k+17)=0
We multiply parentheses
6k-(2k+17)+6=0
We get rid of parentheses
6k-2k-17+6=0
We add all the numbers together, and all the variables
4k-11=0
We move all terms containing k to the left, all other terms to the right
4k=11
k=11/4
k=2+3/4

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