6(j-7)=5(2j+3)

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Solution for 6(j-7)=5(2j+3) equation: 



6(j-7)=5(2j+3)

We move all terms to the left:

6(j-7)-(5(2j+3))=0

We multiply parentheses

6j-(5(2j+3))-42=0



We calculate terms in parentheses: -(5(2j+3)), so:

5(2j+3)

We multiply parentheses

10j+15

Back to the equation:

-(10j+15)



We get rid of parentheses

6j-10j-15-42=0

We add all the numbers together, and all the variables

-4j-57=0

We move all terms containing j to the left, all other terms to the right

-4j=57

j=57/-4

j=-14+1/4

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