6(h+2)=3(h-1)

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Solution for 6(h+2)=3(h-1) equation: 



6(h+2)=3(h-1)

We move all terms to the left:

6(h+2)-(3(h-1))=0

We multiply parentheses

6h-(3(h-1))+12=0



We calculate terms in parentheses: -(3(h-1)), so:

3(h-1)

We multiply parentheses

3h-3

Back to the equation:

-(3h-3)



We get rid of parentheses

6h-3h+3+12=0

We add all the numbers together, and all the variables

3h+15=0

We move all terms containing h to the left, all other terms to the right

3h=-15

h=-15/3

h=-5

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