6(f-5)+4f=30

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Solution for 6(f-5)+4f=30 equation: 



6(f-5)+4f=30

We move all terms to the left:

6(f-5)+4f-(30)=0

We add all the numbers together, and all the variables

4f+6(f-5)-30=0

We multiply parentheses

4f+6f-30-30=0

We add all the numbers together, and all the variables

10f-60=0

We move all terms containing f to the left, all other terms to the right

10f=60

f=60/10

f=6

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