6(d-4)=3(d+9)

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Solution for 6(d-4)=3(d+9) equation: 



6(d-4)=3(d+9)

We move all terms to the left:

6(d-4)-(3(d+9))=0

We multiply parentheses

6d-(3(d+9))-24=0



We calculate terms in parentheses: -(3(d+9)), so:

3(d+9)

We multiply parentheses

3d+27

Back to the equation:

-(3d+27)



We get rid of parentheses

6d-3d-27-24=0

We add all the numbers together, and all the variables

3d-51=0

We move all terms containing d to the left, all other terms to the right

3d=51

d=51/3

d=17

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