6(d-4)-1=8(d+3)+1

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Solution for 6(d-4)-1=8(d+3)+1 equation: 



6(d-4)-1=8(d+3)+1

We move all terms to the left:

6(d-4)-1-(8(d+3)+1)=0

We multiply parentheses

6d-(8(d+3)+1)-24-1=0



We calculate terms in parentheses: -(8(d+3)+1), so:

8(d+3)+1

We multiply parentheses

8d+24+1

We add all the numbers together, and all the variables

8d+25

Back to the equation:

-(8d+25)



We add all the numbers together, and all the variables

6d-(8d+25)-25=0

We get rid of parentheses

6d-8d-25-25=0

We add all the numbers together, and all the variables

-2d-50=0

We move all terms containing d to the left, all other terms to the right

-2d=50

d=50/-2

d=-25

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