6(d-2)+2(d-53)=2

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Solution for 6(d-2)+2(d-53)=2 equation: 



6(d-2)+2(d-53)=2

We move all terms to the left:

6(d-2)+2(d-53)-(2)=0

We multiply parentheses

6d+2d-12-106-2=0

We add all the numbers together, and all the variables

8d-120=0

We move all terms containing d to the left, all other terms to the right

8d=120

d=120/8

d=15

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