6(d+4)-(d+3)=d-1

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Solution for 6(d+4)-(d+3)=d-1 equation: 



6(d+4)-(d+3)=d-1

We move all terms to the left:

6(d+4)-(d+3)-(d-1)=0

We multiply parentheses

6d-(d+3)-(d-1)+24=0

We get rid of parentheses

6d-d-d-3+1+24=0

We add all the numbers together, and all the variables

4d+22=0

We move all terms containing d to the left, all other terms to the right

4d=-22

d=-22/4

d=-5+1/2

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