6(d+3)=48

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Solution for 6(d+3)=48 equation: 



6(d+3)=48

We move all terms to the left:

6(d+3)-(48)=0

We multiply parentheses

6d+18-48=0

We add all the numbers together, and all the variables

6d-30=0

We move all terms containing d to the left, all other terms to the right

6d=30

d=30/6

d=5

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