6(d+3)+2(d-1)=4d+16

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Solution for 6(d+3)+2(d-1)=4d+16 equation: 



6(d+3)+2(d-1)=4d+16

We move all terms to the left:

6(d+3)+2(d-1)-(4d+16)=0

We multiply parentheses

6d+2d-(4d+16)+18-2=0

We get rid of parentheses

6d+2d-4d-16+18-2=0

We add all the numbers together, and all the variables

4d=0

d=0/4

d=0

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