6(c-4)+6=3+c-21

Solution for 6(c-4)+6=3+c-21 equation:

Simplifying
6(c + -4) + 6 = 3 + c + -21

Reorder the terms:
6(-4 + c) + 6 = 3 + c + -21
(-4 * 6 + c * 6) + 6 = 3 + c + -21
(-24 + 6c) + 6 = 3 + c + -21

Reorder the terms:
-24 + 6 + 6c = 3 + c + -21

Combine like terms: -24 + 6 = -18
-18 + 6c = 3 + c + -21

Reorder the terms:
-18 + 6c = 3 + -21 + c

Combine like terms: 3 + -21 = -18
-18 + 6c = -18 + c

Add '18' to each side of the equation.
-18 + 18 + 6c = -18 + 18 + c

Combine like terms: -18 + 18 = 0
0 + 6c = -18 + 18 + c
6c = -18 + 18 + c

Combine like terms: -18 + 18 = 0
6c = 0 + c
6c = c

Solving
6c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
6c + -1c = c + -1c

Combine like terms: 6c + -1c = 5c
5c = c + -1c

Combine like terms: c + -1c = 0
5c = 0

Divide each side by '5'.
c = 0

Simplifying
c = 0