6(c-4)+5=2+c-21

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Solution for 6(c-4)+5=2+c-21 equation: 


Simplifying
6(c + -4) + 5 = 2 + c + -21

Reorder the terms:
6(-4 + c) + 5 = 2 + c + -21
(-4 * 6 + c * 6) + 5 = 2 + c + -21
(-24 + 6c) + 5 = 2 + c + -21

Reorder the terms:
-24 + 5 + 6c = 2 + c + -21

Combine like terms: -24 + 5 = -19
-19 + 6c = 2 + c + -21

Reorder the terms:
-19 + 6c = 2 + -21 + c

Combine like terms: 2 + -21 = -19
-19 + 6c = -19 + c

Add '19' to each side of the equation.
-19 + 19 + 6c = -19 + 19 + c

Combine like terms: -19 + 19 = 0
0 + 6c = -19 + 19 + c
6c = -19 + 19 + c

Combine like terms: -19 + 19 = 0
6c = 0 + c
6c = c

Solving
6c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
6c + -1c = c + -1c

Combine like terms: 6c + -1c = 5c
5c = c + -1c

Combine like terms: c + -1c = 0
5c = 0

Divide each side by '5'.
c = 0

Simplifying
c = 0

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