6(c-2)+2(c-53)=2

Solution for 6(c-2)+2(c-53)=2 equation:

Simplifying
6(c + -2) + 2(c + -53) = 2

Reorder the terms:
6(-2 + c) + 2(c + -53) = 2
(-2 * 6 + c * 6) + 2(c + -53) = 2
(-12 + 6c) + 2(c + -53) = 2

Reorder the terms:
-12 + 6c + 2(-53 + c) = 2
-12 + 6c + (-53 * 2 + c * 2) = 2
-12 + 6c + (-106 + 2c) = 2

Reorder the terms:
-12 + -106 + 6c + 2c = 2

Combine like terms: -12 + -106 = -118
-118 + 6c + 2c = 2

Combine like terms: 6c + 2c = 8c
-118 + 8c = 2

Solving
-118 + 8c = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '118' to each side of the equation.
-118 + 118 + 8c = 2 + 118

Combine like terms: -118 + 118 = 0
0 + 8c = 2 + 118
8c = 2 + 118

Combine like terms: 2 + 118 = 120
8c = 120

Divide each side by '8'.
c = 15

Simplifying
c = 15