6(c+2)=-6(c-4)

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Solution for 6(c+2)=-6(c-4) equation: 



6(c+2)=-6(c-4)

We move all terms to the left:

6(c+2)-(-6(c-4))=0

We multiply parentheses

6c-(-6(c-4))+12=0



We calculate terms in parentheses: -(-6(c-4)), so:

-6(c-4)

We multiply parentheses

-6c+24

Back to the equation:

-(-6c+24)



We get rid of parentheses

6c+6c-24+12=0

We add all the numbers together, and all the variables

12c-12=0

We move all terms containing c to the left, all other terms to the right

12c=12

c=12/12

c=1

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