6(c+1)=2(2c-4)

Solution for 6(c+1)=2(2c-4) equation:

Simplifying
6(c + 1) = 2(2c + -4)

Reorder the terms:
6(1 + c) = 2(2c + -4)
(1 * 6 + c * 6) = 2(2c + -4)
(6 + 6c) = 2(2c + -4)

Reorder the terms:
6 + 6c = 2(-4 + 2c)
6 + 6c = (-4 * 2 + 2c * 2)
6 + 6c = (-8 + 4c)

Solving
6 + 6c = -8 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
6 + 6c + -4c = -8 + 4c + -4c

Combine like terms: 6c + -4c = 2c
6 + 2c = -8 + 4c + -4c

Combine like terms: 4c + -4c = 0
6 + 2c = -8 + 0
6 + 2c = -8

Add '-6' to each side of the equation.
6 + -6 + 2c = -8 + -6

Combine like terms: 6 + -6 = 0
0 + 2c = -8 + -6
2c = -8 + -6

Combine like terms: -8 + -6 = -14
2c = -14

Divide each side by '2'.
c = -7

Simplifying
c = -7