6(c+)=4c-18

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Solution for 6(c+)=4c-18 equation: 



6(c+)=4c-18

We move all terms to the left:

6(c+)-(4c-18)=0

We add all the numbers together, and all the variables

6(+c)-(4c-18)=0

We multiply parentheses

6c-(4c-18)=0

We get rid of parentheses

6c-4c+18=0

We add all the numbers together, and all the variables

2c+18=0

We move all terms containing c to the left, all other terms to the right

2c=-18

c=-18/2

c=-9

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