6(b-7)=(6b+7)2

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Solution for 6(b-7)=(6b+7)2 equation: 



6(b-7)=(6b+7)2

We move all terms to the left:

6(b-7)-((6b+7)2)=0

We multiply parentheses

6b-((6b+7)2)-42=0



We calculate terms in parentheses: -((6b+7)2), so:

(6b+7)2

We multiply parentheses

12b+14

Back to the equation:

-(12b+14)



We get rid of parentheses

6b-12b-14-42=0

We add all the numbers together, and all the variables

-6b-56=0

We move all terms containing b to the left, all other terms to the right

-6b=56

b=56/-6

b=-9+1/3

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