6(b-3)+15=57

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Solution for 6(b-3)+15=57 equation: 



6(b-3)+15=57

We move all terms to the left:

6(b-3)+15-(57)=0

We add all the numbers together, and all the variables

6(b-3)-42=0

We multiply parentheses

6b-18-42=0

We add all the numbers together, and all the variables

6b-60=0

We move all terms containing b to the left, all other terms to the right

6b=60

b=60/6

b=10

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