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6(b-12)+2b=10(3+b)-2b
We move all terms to the left:
6(b-12)+2b-(10(3+b)-2b)=0
We add all the numbers together, and all the variables
6(b-12)+2b-(10(b+3)-2b)=0
We add all the numbers together, and all the variables
2b+6(b-12)-(10(b+3)-2b)=0
We multiply parentheses
2b+6b-(10(b+3)-2b)-72=0
We calculate terms in parentheses: -(10(b+3)-2b), so:We add all the numbers together, and all the variables
10(b+3)-2b
We add all the numbers together, and all the variables
-2b+10(b+3)
We multiply parentheses
-2b+10b+30
We add all the numbers together, and all the variables
8b+30
Back to the equation:
-(8b+30)
8b-(8b+30)-72=0
We get rid of parentheses
8b-8b-30-72=0
We add all the numbers together, and all the variables
-102!=0
There is no solution for this equation
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