6(az-5)=25+bz

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Solution for 6(az-5)=25+bz equation:


Simplifying
6(az + -5) = 25 + bz

Reorder the terms:
6(-5 + az) = 25 + bz
(-5 * 6 + az * 6) = 25 + bz
(-30 + 6az) = 25 + bz

Solving
-30 + 6az = 25 + bz

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '30' to each side of the equation.
-30 + 30 + 6az = 25 + 30 + bz

Combine like terms: -30 + 30 = 0
0 + 6az = 25 + 30 + bz
6az = 25 + 30 + bz

Combine like terms: 25 + 30 = 55
6az = 55 + bz

Divide each side by '6z'.
a = 9.166666667z-1 + 0.1666666667b

Simplifying
a = 9.166666667z-1 + 0.1666666667b

Reorder the terms:
a = 0.1666666667b + 9.166666667z-1

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