6(a-5)=3(3a)+2(a-25)

Solution for 6(a-5)=3(3a)+2(a-25) equation:

6(a-5)=3(3a)+2(a-25)

We move all terms to the left:

6(a-5)-(3(3a)+2(a-25))=0

We multiply parentheses

6a-(33a+2(a-25))-30=0


We calculate terms in parentheses: -(33a+2(a-25)), so:

33a+2(a-25)

We multiply parentheses

33a+2a-50

We add all the numbers together, and all the variables

35a-50

Back to the equation:

-(35a-50)


We get rid of parentheses

6a-35a+50-30=0

We add all the numbers together, and all the variables

-29a+20=0

We move all terms containing a to the left, all other terms to the right

-29a=-20

a=-20/-29

a=20/29