6(a-40)=4(a+20)

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Solution for 6(a-40)=4(a+20) equation: 



6(a-40)=4(a+20)

We move all terms to the left:

6(a-40)-(4(a+20))=0

We multiply parentheses

6a-(4(a+20))-240=0



We calculate terms in parentheses: -(4(a+20)), so:

4(a+20)

We multiply parentheses

4a+80

Back to the equation:

-(4a+80)



We get rid of parentheses

6a-4a-80-240=0

We add all the numbers together, and all the variables

2a-320=0

We move all terms containing a to the left, all other terms to the right

2a=320

a=320/2

a=160

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