6(a-3)+10=2(4x-5)

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Solution for 6(a-3)+10=2(4x-5) equation:


Simplifying
6(a + -3) + 10 = 2(4x + -5)

Reorder the terms:
6(-3 + a) + 10 = 2(4x + -5)
(-3 * 6 + a * 6) + 10 = 2(4x + -5)
(-18 + 6a) + 10 = 2(4x + -5)

Reorder the terms:
-18 + 10 + 6a = 2(4x + -5)

Combine like terms: -18 + 10 = -8
-8 + 6a = 2(4x + -5)

Reorder the terms:
-8 + 6a = 2(-5 + 4x)
-8 + 6a = (-5 * 2 + 4x * 2)
-8 + 6a = (-10 + 8x)

Solving
-8 + 6a = -10 + 8x

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 6a = -10 + 8 + 8x

Combine like terms: -8 + 8 = 0
0 + 6a = -10 + 8 + 8x
6a = -10 + 8 + 8x

Combine like terms: -10 + 8 = -2
6a = -2 + 8x

Divide each side by '6'.
a = -0.3333333333 + 1.333333333x

Simplifying
a = -0.3333333333 + 1.333333333x

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