6(C-5)+4=2+C-28

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Solution for 6(C-5)+4=2+C-28 equation: 


Simplifying
6(C + -5) + 4 = 2 + C + -28

Reorder the terms:
6(-5 + C) + 4 = 2 + C + -28
(-5 * 6 + C * 6) + 4 = 2 + C + -28
(-30 + 6C) + 4 = 2 + C + -28

Reorder the terms:
-30 + 4 + 6C = 2 + C + -28

Combine like terms: -30 + 4 = -26
-26 + 6C = 2 + C + -28

Reorder the terms:
-26 + 6C = 2 + -28 + C

Combine like terms: 2 + -28 = -26
-26 + 6C = -26 + C

Add '26' to each side of the equation.
-26 + 26 + 6C = -26 + 26 + C

Combine like terms: -26 + 26 = 0
0 + 6C = -26 + 26 + C
6C = -26 + 26 + C

Combine like terms: -26 + 26 = 0
6C = 0 + C
6C = C

Solving
6C = C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-1C' to each side of the equation.
6C + -1C = C + -1C

Combine like terms: 6C + -1C = 5C
5C = C + -1C

Combine like terms: C + -1C = 0
5C = 0

Divide each side by '5'.
C = 0

Simplifying
C = 0

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