6(9y-1)-10-(5y)-3y=22-4(2y-12)+8(y-6)

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Solution for 6(9y-1)-10-(5y)-3y=22-4(2y-12)+8(y-6) equation: 



6(9y-1)-10-(5y)-3y=22-4(2y-12)+8(y-6)

We move all terms to the left:

6(9y-1)-10-(5y)-3y-(22-4(2y-12)+8(y-6))=0

We add all the numbers together, and all the variables

-8y+6(9y-1)-(22-4(2y-12)+8(y-6))-10=0

We multiply parentheses

-8y+54y-(22-4(2y-12)+8(y-6))-6-10=0



We calculate terms in parentheses: -(22-4(2y-12)+8(y-6)), so:

22-4(2y-12)+8(y-6)

determiningTheFunctionDomain
-4(2y-12)+8(y-6)+22

We multiply parentheses

-8y+8y+48-48+22

We add all the numbers together, and all the variables

22

Back to the equation:

-(22)



We add all the numbers together, and all the variables

46y-38=0

We move all terms containing y to the left, all other terms to the right

46y=38

y=38/46

y=19/23

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