6(9x-5)-3=5(2-x)+8(x+5)

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Solution for 6(9x-5)-3=5(2-x)+8(x+5) equation: 



6(9x-5)-3=5(2-x)+8(x+5)

We move all terms to the left:

6(9x-5)-3-(5(2-x)+8(x+5))=0

We add all the numbers together, and all the variables

6(9x-5)-(5(-1x+2)+8(x+5))-3=0

We multiply parentheses

54x-(5(-1x+2)+8(x+5))-30-3=0



We calculate terms in parentheses: -(5(-1x+2)+8(x+5)), so:

5(-1x+2)+8(x+5)

We multiply parentheses

-5x+8x+10+40

We add all the numbers together, and all the variables

3x+50

Back to the equation:

-(3x+50)



We add all the numbers together, and all the variables

54x-(3x+50)-33=0

We get rid of parentheses

54x-3x-50-33=0

We add all the numbers together, and all the variables

51x-83=0

We move all terms containing x to the left, all other terms to the right

51x=83

x=83/51

x=1+32/51

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