6(8t+1)-13=t-(t+6)

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Solution for 6(8t+1)-13=t-(t+6) equation: 



6(8t+1)-13=t-(t+6)

We move all terms to the left:

6(8t+1)-13-(t-(t+6))=0

We multiply parentheses

48t-(t-(t+6))+6-13=0



We calculate terms in parentheses: -(t-(t+6)), so:

t-(t+6)

We get rid of parentheses

t-t-6

We add all the numbers together, and all the variables

-6

Back to the equation:

-(-6)



We add all the numbers together, and all the variables

48t-1=0

We move all terms containing t to the left, all other terms to the right

48t=1

t=1/48

t=1/48

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