6(8+3x)=-2(x-4)

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Solution for 6(8+3x)=-2(x-4) equation: 



6(8+3x)=-2(x-4)

We move all terms to the left:

6(8+3x)-(-2(x-4))=0

We add all the numbers together, and all the variables

6(3x+8)-(-2(x-4))=0

We multiply parentheses

18x-(-2(x-4))+48=0



We calculate terms in parentheses: -(-2(x-4)), so:

-2(x-4)

We multiply parentheses

-2x+8

Back to the equation:

-(-2x+8)



We get rid of parentheses

18x+2x-8+48=0

We add all the numbers together, and all the variables

20x+40=0

We move all terms containing x to the left, all other terms to the right

20x=-40

x=-40/20

x=-2

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