6(7z-8)=-33+9z

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Solution for 6(7z-8)=-33+9z equation: 



6(7z-8)=-33+9z

We move all terms to the left:

6(7z-8)-(-33+9z)=0

We add all the numbers together, and all the variables

6(7z-8)-(9z-33)=0

We multiply parentheses

42z-(9z-33)-48=0

We get rid of parentheses

42z-9z+33-48=0

We add all the numbers together, and all the variables

33z-15=0

We move all terms containing z to the left, all other terms to the right

33z=15

z=15/33

z=5/11

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