6(7t+1)-10=t-(t+3)

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Solution for 6(7t+1)-10=t-(t+3) equation:



6(7t+1)-10=t-(t+3)
We move all terms to the left:
6(7t+1)-10-(t-(t+3))=0
We multiply parentheses
42t-(t-(t+3))+6-10=0
We calculate terms in parentheses: -(t-(t+3)), so:
t-(t+3)
We get rid of parentheses
t-t-3
We add all the numbers together, and all the variables
-3
Back to the equation:
-(-3)
We add all the numbers together, and all the variables
42t-1=0
We move all terms containing t to the left, all other terms to the right
42t=1
t=1/42
t=1/42

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