6(7-f)=5(2f+2)

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Solution for 6(7-f)=5(2f+2) equation: 



6(7-f)=5(2f+2)

We move all terms to the left:

6(7-f)-(5(2f+2))=0

We add all the numbers together, and all the variables

6(-1f+7)-(5(2f+2))=0

We multiply parentheses

-6f-(5(2f+2))+42=0



We calculate terms in parentheses: -(5(2f+2)), so:

5(2f+2)

We multiply parentheses

10f+10

Back to the equation:

-(10f+10)



We get rid of parentheses

-6f-10f-10+42=0

We add all the numbers together, and all the variables

-16f+32=0

We move all terms containing f to the left, all other terms to the right

-16f=-32

f=-32/-16

f=+2

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