6(7+z)-4(z+2)=3(z-1)

Solution for 6(7+z)-4(z+2)=3(z-1) equation:

Simplifying
6(7 + z) + -4(z + 2) = 3(z + -1)
(7 * 6 + z * 6) + -4(z + 2) = 3(z + -1)
(42 + 6z) + -4(z + 2) = 3(z + -1)

Reorder the terms:
42 + 6z + -4(2 + z) = 3(z + -1)
42 + 6z + (2 * -4 + z * -4) = 3(z + -1)
42 + 6z + (-8 + -4z) = 3(z + -1)

Reorder the terms:
42 + -8 + 6z + -4z = 3(z + -1)

Combine like terms: 42 + -8 = 34
34 + 6z + -4z = 3(z + -1)

Combine like terms: 6z + -4z = 2z
34 + 2z = 3(z + -1)

Reorder the terms:
34 + 2z = 3(-1 + z)
34 + 2z = (-1 * 3 + z * 3)
34 + 2z = (-3 + 3z)

Solving
34 + 2z = -3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
34 + 2z + -3z = -3 + 3z + -3z

Combine like terms: 2z + -3z = -1z
34 + -1z = -3 + 3z + -3z

Combine like terms: 3z + -3z = 0
34 + -1z = -3 + 0
34 + -1z = -3

Add '-34' to each side of the equation.
34 + -34 + -1z = -3 + -34

Combine like terms: 34 + -34 = 0
0 + -1z = -3 + -34
-1z = -3 + -34

Combine like terms: -3 + -34 = -37
-1z = -37

Divide each side by '-1'.
z = 37

Simplifying
z = 37