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6(7+2x)=3(5x+1)
We move all terms to the left:
6(7+2x)-(3(5x+1))=0
We add all the numbers together, and all the variables
6(2x+7)-(3(5x+1))=0
We multiply parentheses
12x-(3(5x+1))+42=0
We calculate terms in parentheses: -(3(5x+1)), so:We get rid of parentheses
3(5x+1)
We multiply parentheses
15x+3
Back to the equation:
-(15x+3)
12x-15x-3+42=0
We add all the numbers together, and all the variables
-3x+39=0
We move all terms containing x to the left, all other terms to the right
-3x=-39
x=-39/-3
x=+13
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