6(6+2x+12)=10(x+3)

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Solution for 6(6+2x+12)=10(x+3) equation: 



6(6+2x+12)=10(x+3)

We move all terms to the left:

6(6+2x+12)-(10(x+3))=0

We add all the numbers together, and all the variables

6(2x+18)-(10(x+3))=0

We multiply parentheses

12x-(10(x+3))+108=0



We calculate terms in parentheses: -(10(x+3)), so:

10(x+3)

We multiply parentheses

10x+30

Back to the equation:

-(10x+30)



We get rid of parentheses

12x-10x-30+108=0

We add all the numbers together, and all the variables

2x+78=0

We move all terms containing x to the left, all other terms to the right

2x=-78

x=-78/2

x=-39

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