6(5c-3)=3(-4+9c)

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Solution for 6(5c-3)=3(-4+9c) equation: 



6(5c-3)=3(-4+9c)

We move all terms to the left:

6(5c-3)-(3(-4+9c))=0

We add all the numbers together, and all the variables

6(5c-3)-(3(9c-4))=0

We multiply parentheses

30c-(3(9c-4))-18=0



We calculate terms in parentheses: -(3(9c-4)), so:

3(9c-4)

We multiply parentheses

27c-12

Back to the equation:

-(27c-12)



We get rid of parentheses

30c-27c+12-18=0

We add all the numbers together, and all the variables

3c-6=0

We move all terms containing c to the left, all other terms to the right

3c=6

c=6/3

c=2

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