6(5c+2)-2c=3(2c+3)

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Solution for 6(5c+2)-2c=3(2c+3) equation: 



6(5c+2)-2c=3(2c+3)

We move all terms to the left:

6(5c+2)-2c-(3(2c+3))=0

We add all the numbers together, and all the variables

-2c+6(5c+2)-(3(2c+3))=0

We multiply parentheses

-2c+30c-(3(2c+3))+12=0



We calculate terms in parentheses: -(3(2c+3)), so:

3(2c+3)

We multiply parentheses

6c+9

Back to the equation:

-(6c+9)



We add all the numbers together, and all the variables

28c-(6c+9)+12=0

We get rid of parentheses

28c-6c-9+12=0

We add all the numbers together, and all the variables

22c+3=0

We move all terms containing c to the left, all other terms to the right

22c=-3

c=-3/22

c=-3/22

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