6(5+y)-3(1-y)=4(9+2y)-12

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Solution for 6(5+y)-3(1-y)=4(9+2y)-12 equation: 



6(5+y)-3(1-y)=4(9+2y)-12

We move all terms to the left:

6(5+y)-3(1-y)-(4(9+2y)-12)=0

We add all the numbers together, and all the variables

6(y+5)-3(-1y+1)-(4(2y+9)-12)=0

We multiply parentheses

6y+3y-(4(2y+9)-12)+30-3=0



We calculate terms in parentheses: -(4(2y+9)-12), so:

4(2y+9)-12

We multiply parentheses

8y+36-12

We add all the numbers together, and all the variables

8y+24

Back to the equation:

-(8y+24)



We add all the numbers together, and all the variables

9y-(8y+24)+27=0

We get rid of parentheses

9y-8y-24+27=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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