6(4z-1)-4(z+1)=3(z+1)

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Solution for 6(4z-1)-4(z+1)=3(z+1) equation:


6(4z-1)-4(z+1)=3(z+1)

We simplify the equation to the form, which is simple to understand 
6(4z-1)-4(z+1)=3(z+1)

Reorder the terms in parentheses
+(+24z-6)-4*(z+1)=3*(z+1)

Remove unnecessary parentheses
+24z-6-4+*(+z+1+)=+3+*(+z+1+)

Reorder the terms in parentheses
+24z-6+(-4z-4)=3*(z+1)

Remove unnecessary parentheses
+24z-6-4z-4=+3+*(+z+1+)

Reorder the terms in parentheses
+24z-6-4z-4=+(+3z+3)

Remove unnecessary parentheses
+24z-6-4z-4=+3z+3

We move all terms containing z to the left and all other terms to the right. 
+24z-4z-3z=+3+6+4

We simplify left and right side of the equation. 
+17z=+13

We divide both sides of the equation by 17 to get z. 
z=0.764705882353

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